题解 | #奇偶统计#
奇偶统计
https://www.nowcoder.com/practice/04de8eb0ecab426fa6be3ae99af17210
#include<stdio.h>
int main()
{
int N,ji=0,ou=0;
scanf("%d",&N);
for(int i=1;i<=N;i++){
if(i%2) ji++;
else ou++;
}
printf("%d %d",ji,ou);
return 0;
}
