题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include <iostream>
using namespace std;
long long JC(int n)
{
if(n==1)return 1;
else
return n*JC(n-1);
}
int main() {
int n;
while (cin >>n) {
cout<<JC(n)<<endl;
}
}