题解 | #整数与IP地址间的转换#
整数与IP地址间的转换
https://www.nowcoder.com/practice/66ca0e28f90c42a196afd78cc9c496ea
#include <array>
#include <cstddef>
#include <iostream>
#include <string>
using namespace std;
int main() {
array<long, 4> ip{0,0,0,0};
string strin;
long longin;
scanf("%ld.%ld.%ld.%ld%ld",&ip[0],&ip[1],&ip[2],&ip[3],&longin);
long out=ip[0]<<24 | ip[1]<<16 | ip[2]<<8 | ip[3];
cout<<out<<endl;
string outstr;
outstr.clear();
outstr+=to_string(longin>>24 & 0xff);
outstr+='.';
outstr+=to_string(longin>>16 & 0xff);
outstr+='.';
outstr+=to_string(longin>>8 & 0xff);
outstr+='.';
outstr+=to_string(longin & 0xff);
cout<<outstr<<endl;
}
// 64 位输出请用 printf("%lld")
