题解 | #简单表达式计算#

# 读入表达式，调用eval函数，三行搞定。
import sys
inp = sys.stdin.read().strip().split("\n")[:-1]
for s in inp: print(eval(s))


# def calc(a, b, op):
#     # print(a,b,op)
#     if '+'==op: return a+b
#     if '-'==op: return a-b
#     if '*'==op: return a*b
#     assert("error")

# op = set('+-*')
# for s in inp:
#     # print(eval(s))
#     stack0 = []
#     stack1 = []
#     i = 0
#     while i<len(s):
#         if s[i] not in op:
#             j=i+1
#             while j<len(s) and s[j] not in op: j+=1
#             stack0.append(int(s[i:j]))
#             i = j
#         else: 
#             o = s[i]
#             if o=="*": stack1.append(o)
#             else:
#                 while len(stack1):
#                     b, a = stack0.pop(), stack0.pop()
#                     c = calc(a,b,stack1.pop())
#                     stack0.append(c)
#                 stack1.append(o)
#             i+=1

#     while len(stack1):
#         b, a = stack0.pop(), stack0.pop()
#         c = calc(a,b,stack1.pop())
#         stack0.append(c)
#     print(stack0[0])