题解 | #牛客每个人最近的登录日期(二)#

牛客每个人最近的登录日期(二)

https://www.nowcoder.com/practice/7cc3c814329546e89e71bb45c805c9ad

先查找到max(date) group by user_id,条件要有l.date=l2.date!


select u.name as u_n,
c.name as c_name ,
l.date as date 
from login l 
inner join (select user_id,max(date) as date from login  group by user_id ) as l2 on l.user_id=l2.user_id and l.date=l2.date
left join user u on u.id =l.user_id
left join client c on c.id=l.client_id 
order by u.name;

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