题解 | #小乐乐与进制转换#

#include <stdio.h>

int main() 
{
    //考虑溢出
    long long num;
    long long result = 0;
    long long s = 1;
    scanf("%lld",&num);
    while(num!=0)
    {
        int wei = num%6;
        result +=(wei*s);
        s *= 10;
        num /= 6;
    }
    printf("%lld",result);
    return 0;
}