题解 | #坐标移动#

/*没看到最高两位数的情况下做的，可以识别位数，并输出*/
#include<iostream>
#include<vector>
#include<string>
#include<math.h>

using namespace std;

void movement(string str)
{
	vector<string> v;
	int x = 0, y = 0;
	int sub = 0;
	string s0;
	for (int i = 0; i < str.size(); i++)
	{
		if (str[i] != ';')
		{
			sub++;
			s0.push_back(str[i]);
			continue;
		}
		else
		{
			v.push_back(s0);
			sub = 0;
			s0.clear();
			continue;
		}
	}
	vector<int> num;
	num.resize(v.size());
	for (int i = 0; i < v.size(); i++)
	{
		int len = v[i].size();
		for (int j = 1; j < len; j++)
		{
			if (v[i][j] >= '0' && v[i][j] <= '9')
			{
				num[i] += (v[i][j] - '0') * pow(10, len - 1 - j);
				continue;
			}
			else
			{
				v[i] = "False";
				break;
			}
		}
	}
	for (int i = 0; i < v.size(); i++)
	{
		switch (v[i][0])
		{
		case'A':
			x -= num[i]; break;
		case'D':
			x += num[i]; break;
		case'W':
			y += num[i]; break;
		case'S':
			y -= num[i]; break;

		default:
			break;
		}
	}
	cout << x << "," << y << endl;
}

int main()
{
	string s;
	getline(cin, s);
	movement(s);
	
	return 0;
}
// 64 位输出请用 printf("%lld")