题解 | #字符串的反码#

#include <stdio.h>
#include <string.h>

int main() {
    char s[80];
    scanf("%s", s);
    for (int i = 0; i < strlen(s); i++) {
        if (s[i] >= 'a' && s[i] <= 'm') {
            s[i] = 'z'- (s[i] - 'a');
        } else if (s[i] >= 'n' && s[i] <= 'z') {
            s[i] = 'a' + ('z' - s[i]);
        } else if (s[i] >= 'A' && s[i] <= 'M') {
            s[i] = 'Z' - (s[i] - 'A');
        } else if (s[i] >= 'N' && s[i] <= 'Z') {
            s[i] = 'A' + ('Z' - s[i]);
        }
    }
    printf("%s\n", s);
    return 0;
}