题解 | #在字符串中找出连续最长的数字串#

while 1:
    try:
        s = input()

        s0 = [[], []]

        counter = 0
        mark = 0

        for i in range(len(s)):
            if i + 1 != len(s) and s[i].isdigit() and s[i + 1].isdigit():
                if i + 2 != len(s):
                    counter += 1
                    continue
                elif i + 2 == len(s) and s[i + 1].isdigit():
                    counter += 2
                    s0[0].append(s[i + 2 - counter : ])
                    s0[1].append(counter)
                    counter = 0
                    break

            elif counter >= 1 and s[i].isdigit() and i + 1 != len(s) and not s[i + 1].isdigit():
                counter += 1
                s0[0].append(s[i - counter + 1 : i + 1])
                s0[1].append(counter)
                counter = 0

            elif counter == 0 and s[i].isdigit():
                counter += 1
                s0[0].append(s[i - counter + 1 : i + 1])
                s0[1].append(counter)
                counter = 0

        mark = max(s0[1])
        for i in range(len(s0[0])):
            if len(s0[0][i]) == mark:
                print(s0[0][i], end='')
            else:
                continue
        print(',', end='')
        print(mark)

    except:
        break