题解 | #序列重组矩阵#
序列重组矩阵
https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966
#include <stdio.h>
int main() {
int m,n;
int i,j;
int arr[20] = {0};
scanf("%d%d",&m,&n);
for(i=0;i<n*m;i++)
{
scanf("%d",&arr[i]);
}
int a = 0;
for(j=1;j<n*m+1;j++)
{
if(j%n!=0)
{
printf("%d ",arr[j-1]);
}
else
{
printf("%d\n",arr[j-1]);
}
}
return 0;
}
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