题解 | #等差数列#
等差数列
https://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <stdio.h>
int main()
{
int n = 0;
while (scanf("%d ", &n) != EOF)
{ // 注意 while 处理多个 case
// 64 位输出请用 printf("%lld") to
int a1 = 2;
int d = 3;
int sn = 0;
sn = n * a1 + (n * (n - 1) *d / 2);
printf("%d\n",sn);
}
return 0;
}
查看6道真题和解析
把实习去了一天嗷嗷投简历就完事了
