题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <iostream>
using namespace std;
int main()
{
long seconds;
cin >> seconds;
int h, m, s;
// 除 求模运算
h = seconds / (60 * 60);
m = (seconds % (60 * 60)) / 60;
s = seconds % 60;
cout << h << " " << m << " " << s << endl;
return 0;
}
