题解 | #翻转金字塔图案#

#include <stdio.h>

int main() {
    int n;
    while (scanf("%d", &n) != EOF)
    {
        for (int i = 1; i <= n; i++)
        {
            for (int j = 1; j < i; j++)
            {
                printf(" ");
            }
            for (int k = 0; k <= n - i; k++)
            {
                printf("* ");
            }
            
            printf("\n");
        }
    }
    return 0;
}