题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型一维数组
* @param numsLen int nums数组长度
* @param target int整型
* @return int整型
*/
int search(int* nums, int numsLen, int target ) {
// write code here
int left = 0,right = numsLen,temp;
if(numsLen == 0)
return -1;
if(numsLen == 1)
{
if(nums[0] == target)
return 0;
else
return -1;
}
if(numsLen ==2)
{
if(nums[0] == target)
return 0;
if(nums[1]==target)
return 1;
else
return -1;
}
while(left != right-1)
{
temp = (left+right)/2;
if(nums[temp]>target)
{
right = temp;
}
if(nums[temp]<target)
{
left = temp;
}
if(nums[temp]==target)
{
return temp;
}
}
return -1;
}

