题解 | #求最大连续bit数#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here
    let n;
    while ((line = await readline())) {
        n = +line;
    }
    let str = n.toString(2);
    //利用match加正则=>匹配出连续1的子字符串集
    let filter = str.match(/1+/g);
    let maxlen = 0;
    //求得子字符串数组中元素的最大长度即是最终所求
    for (let item of filter) {
        if (item.length > maxlen) {
            maxlen = item.length;
        }
    }
    console.log(maxlen);
})();