题解 | #平均活跃天数和月活人数#

平均活跃天数和月活人数

https://www.nowcoder.com/practice/9e2fb674b58b4f60ac765b7a37dde1b9

select
    month
    ,round(sum(active_days)/count(uid),2) as avg_active_days
    ,count(uid) as mau
from
(
    select 
        date_format(submit_time,'%Y%m') as month
        ,uid
        ,count(distinct day(submit_time)) as active_days
    from exam_record
    where year(submit_time) in (2021)
    group by 
        date_format(submit_time,'%Y%m')
        ,uid
) t
group by
    month

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