题解 | #求最小公倍数#

#include <iostream>
using namespace std;

int main() {
    int a, b;
    cin >> a >> b;
    if(max(a,b) % min(a,b) ==0) cout << max(a,b);
    else{
    for(int i =min(a,b)/2; i>=1; i--){
        if(a % i ==0 && b % i ==0){
            cout << a*b/i;
            break;
        }

    }
    }
}