题解 | #旋转数组的最小数字#
旋转数组的最小数字
https://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
/**
*
* @param rotateArray int整型一维数组
* @param rotateArrayLen int rotateArray数组长度
* @return int整型
*/
int minNumberInRotateArray(int* rotateArray, int rotateArrayLen ) {
// write code here
int * p = &rotateArray[rotateArrayLen - 1];
int count = 0;
while ((count < rotateArrayLen) && (*p >= *(p-1)))
{
p--;
count++;
}
if (count == rotateArrayLen)
p = &rotateArray[0];
return *p;
}

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