题解 | #质数因子#
质数因子
https://www.nowcoder.com/practice/196534628ca6490ebce2e336b47b3607
import math
num =int(input())
for i in range(2, int(math.sqrt(num))+1):
while num%i == 0: #不能用if,会漏相同的因子
print(i, end=' ')
num=int(num/i) #或者用‘//’,除法取整
if num>2:
print(num)
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