题解 | #复杂链表的复制#
复杂链表的复制
https://www.nowcoder.com/practice/f836b2c43afc4b35ad6adc41ec941dba
# -*- coding:utf-8 -*- # class RandomListNode: # def __init__(self, x): # self.label = x # self.next = None # self.random = None class Solution: # 返回 RandomListNode def Clone(self, pHead): # write code here if pHead is None: return None # 定义个字典用于返回值 dict = {} # 定义一个临时结点 cur = pHead # 将字典结点化 while cur: dict[cur] = RandomListNode(cur.label) cur = cur.next # 字典next,random指针开始指向对应的值 cur = pHead while cur: dict[cur].next = dict.get(cur.next) dict[cur].random = dict.get(cur.random) cur = cur.next return dict[pHead]#23届找工作求助阵地#