题解 | #名字的漂亮度#

def headle(s):
    d = dict()
    for i in s:
        if i not in d:
            d[i] = 1
        else:
            d[i] = d[i] + 1
    values = list(d.values())
    values.sort(reverse=True)
    p = 0
    for j in range(len(values)):
        p = p + values[j]*(26-j)
    return p
while True:
    try:
        n = int(input())
        for i in range(n):
            s = input()
            pl = headle(s)
            print(pl)
    except:
        break