题解 | #字符串合并处理#
字符串合并处理
https://www.nowcoder.com/practice/d3d8e23870584782b3dd48f26cb39c8f
str1,str2 = input().split()
he = str1 + str2
he_1 = he[::2]
if len(he) % 2 == 0:
he_2 = he[1::2]
elif len(he) % 2 == 1:
he_2 = he[1:-1:2]
he_1 = sorted(he_1)
he_2 = sorted(he_2)
xin = ''
if len(he) % 2 == 0:
for i in range(int(len(he)/2)):
xin += he_1[i]
xin += he_2[i]
elif len(he) % 2 == 1:
for i in range(int(len(he)/2)+1):
xin += he_1[i]
if len(he_2)-1 >= i:
xin += he_2[i]
xin_list = []
for i in xin:
if i in '0123456789ABCDEFabcdef':
zhi = int(i,16)
zhi = bin(zhi).replace('0b','')
zhi = (4-len(zhi))*'0' + zhi
zhi = zhi[::-1]
zhi = int(zhi,2)
zhi = hex(zhi).replace('0x','').upper()
xin_list.append(zhi)
else:
xin_list.append(i)
res = print(''.join(xin_list)
按照题意，一步一步写下来就好。没有用正则，但是感觉应该要用正则。
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