题解 | #获取 url 参数#

function getUrlParam(sUrl, sKey) {
  let arr = sUrl.split("?")[1].split("#")[0].split("&");
  const obj = {};
  arr.forEach((item) => {
    const subObj = item.split("=");
    if (!Object.keys(obj).includes(subObj[0])) {
      obj[subObj[0]] = subObj[1];
    } else {
      obj[subObj[0]] = [...obj[subObj[0]], ...subObj[1]];
    }
  });
  return sKey===void 0 ? obj:obj[sKey]||''