PAT A 1005

/*
    没必要数组保存,直接getchar
    然后转化成英文就好了
*/
#include<cstdio>
#include<string>
using namespace std;
int main()
{
    int c;
    int sum = 0;
    char EngNum[10][10] = {"zero","one","two","three","four","five","six","seven","eight","nine"};
    while((c=getchar())!='\n')
        sum += c-'0';
    string str = to_string(sum);
    int len = str.length();
    for(int i = 0; i<len; ++i)
    {
        if(i!=0)
            printf(" ");
        printf("%s",EngNum[str[i]-'0']);
    }
    printf("\n");
    return 0;
}
全部评论

相关推荐

点赞 收藏 评论
分享
牛客网
牛客企业服务