解析: 将B[i]=A[0]*A[1]*...*A[i-1]*A[i+1]*...*A[n-1]拆分成两个部分A[0]*A[1]*...*A[i-1]和A[i+1]*...*A[n-1],分别记为L[i]和R[i],则B[i] = L[i] * R[i] 结合B[0] = A[1] * A[2] * ... * A[n-1],根据1类比,得出L[0] = 1,R[0] = A[1] * A[2] * ... * A[n-1] 结合B[n-1] = A[0] * A[1] * ... * A[n-2],根据1类比,得出L[n-1]=A[0] * A[1] * ... * A[n-2], R[n...