# 查询所有字段+提取年龄列 select *, substring_index(substring_index(profile,',',3),',',-1) age from user_submit # 返回每个年龄的用户数 select age, count(*) number from( select *, substring_index(substring_index(profile,',',3),',',-1) age from user_submit ) age_f group by age; /*substring_index(str, delim, count)*/# 如果c...