题目描述 如果三个正整数A、B、C ,A² + B² = C² 则为勾股数,如果ABC之间两两互质,即A与B,A与C,B与C均互质没有公约数,则称其为勾股数元组。请求出给定 n ~ m 范围内所有的勾股数元组。输入描述起始范围1 < n < 10000n < m < 10000输出描述ABC保证A < B < C输出格式A B C多组勾股数元组,按照A B C升序的排序方式输出。若给定范围内,找不到勾股数元组时,输出Na。import java.util.Scanner;public class Main {public static void main(String[] args) {Scanner in = new Scanner(System.in);while (in.hasNextInt()) {int n = in.nextInt();int m = in.nextInt();boolean found = false;for (int i = n; i <= m; i++) {for (int j = i + 1; j <= m; j++) {int k = (int) Math.sqrt(i * i + j * j);if (k > m) {break;}if (k * k == i * i + j * j) {if (gcd(i, j) == 1 &amp;&amp; gcd(j, k) == 1) {System.out.printf(&quot;%d %d %d\\n&quot;, i, j, k);found = true;}}}}if (!found) {System.out.println(&quot;Na&quot;);}}}private static int gcd(int a, int b) {return b == 0 ? a : gcd(b, a % b);}}