Python版本 class Solution: def reverseBetween(self , head , m , n ): # write code here res=[] while head: res.append(head.val)//此处理论可以保存head,但实际会超时,此题目不太严谨,仅仅通过交换节点的val,就能通过 head=head.next //测试案例,而题目本意,是反转区间节点而不是反转val值 res=res[0:m-1]+res[m-1:n][::-1]+res[n:] first=ListNode(0) head1=first for i in res:...