1. 满***换律:A^B = B^A 2. 满足结合律:(A^B)^C = A^(B^C) 3. 0^A = A 4. A^A = 0 nums = {a1,a2, b1, b2, c1} 0^a1^b1^c1^b2^a1 0^(a1^a2)^(b1^b2)^c1 0^0^0^c1 c1 int a = 0; for(auto i : nums) a ^= i; return a;
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