计算天数

import datetime
n = int(input())
for i in range(n):
    [y,m,p(int, input().split())
    print((datetime.datetime(y,m,d)-datetime.datetime(y,1,1)).days + 1)

import datetime
for _ in range(int(input())):
    y, m, d = map(int, input().split())
    today = datetime.datetime(y, m, d)
    day0 = datetime.datetime(y, 1, 1)
    days = today-day0
    print(days.days+1)

while True:
    try:
        m=int(input().strip())
        def isrunnian(i):
            if i%4==0 and i%100!=0:
                return True
            elif i%400==0:
                return True
            else:
                return False
        list1=[31,28,31,30,31,30,31,31,30,31,30,31]
        list2=[31,29,31,30,31,30,31,31,30,31,30,31]
        for i in range(m):
            inp=list(map(int,input().strip().split(' ')))
            year=inp[0]
            month=inp[1]
            day=inp[2]
            if isrunnian(year):
                result=sum(list2[:month-1])+day
            else:
                result=sum(list1[:month-1])+day
            print(result)
    except:
        break

python解法

3行：

import datetime
for i in range(int(input())):
    print(datetime.datetime(*map(int, input().split())).strftime("%j").lstrip("0"))

5行：

import datetime
for i in range(int(input())):
    a, b, c = map(int, input().split())
    dd = datetime.datetime(a, b, c)
    print(dd.strftime("%j").lstrip("0"))