对于任意两个正整数x和k,我们定义repeat(x, k)为将x重复写k次形成的数,例如repeat(1234, 3) = 123412341234,repeat(20,2) = 2020.
牛牛现在给出4个整数x1, k1, x2, k2, 其中v1 = (x1, k1), v2 = (x2, k2),请你来比较v1和v2的大小。
输入包括一行,一行中有4个正整数x1, k1, x2, k2(1 ≤ x1,x2 ≤ 10^9, 1 ≤ k1,k2 ≤ 50),以空格分割
如果v1小于v2输出"Less",v1等于v2输出"Equal",v1大于v2输出"Greater".
1010 3 101010 2
Equal
def my_atoi(s): if s == '': return 0 else: try: f = float(s) i = int(f) except: return 0 else: return i def test9(): v1, c1, v2, c2 = input().split() str1, str2 = '', '' for i in range(my_atoi(c1)): str1 = str1 + v1 for i in range(my_atoi(c2)): str2 = str2 + v2 if my_atoi(str1) == my_atoi(str2): print('Equal') elif my_atoi(str1) > my_atoi(str2): print('Greater') elif my_atoi(str1) < my_atoi(str2): print('Less') if __name__ == '__main__': test9()
n=input().split(' ') a=int(str(n[0])*int(n[1])) b=int(str(n[2])*int(n[3])) if a>b: print('Greater') elif a<b: print('Less') else: print('Equal')
def answer(v1, v2): if v1 == v2: return 'Equal' else: return 'Greater' if v1 > v2 else 'Less' x1, k1, x2, k2 = input().split() s1 = '' s2 = '' for i in range(int(k1)): s1+=x1 for i in range(int(k2)): s2+=x2 print(answer(int(s1), int(s2)))