with table1(customer_id,city,loan_amount,loan_type_id,loan_type_name,cnt) as ( select l.customer_id,city,loan_amount,t.loan_type_id,t.loan_type_name,count(l.customer_id) over(partition by city,t.loan_type_name) as cnt from loan_applications l join customers c on l.customer_id=c.customer_id join (sel...