使用最小堆排序任务集,贪心策略为每次加入和上一个活动时间不冲突的,结束时间最早的活动 import heapq n = int(input()) tasks = [] for _ in range(n): a, b = map(int, input().split()) heapq.heappush(tasks, (b, a)) end = 0 count = 0 while tasks: b, a = heapq.heappop(tasks) if a >=...