[1,2,3,4][5,6,7,8][9,10,11,12][13,14,15,16]思路:1.输出第一行: ans=[1,2,3,4]2.然后把剩下的矩阵逆时针旋转90度:[8,12,16][7,11,15][6,10,14][5,9,13]3.重复以上操作:ans=[1,2,3,4,8,12,16][15,14,13][11,10,9][7,6,5]4.直到矩阵为空 c++代码: class Solution { public: vector<vector<int> > rotate(vector<vector<int> > ma...