从最后一位开始正常的累加,当前位为sum / 10,进位为sum % 10,每一位存的结果存在stack中,最后输出stack即可 #include <iostream> #include <stack> using namespace std; int main() { string num1, num2; while (cin >> num1 >> num2) { int i = num1.length() - 1, j = num2.length() - 1, n1, n2, carry = 0; ...