对于employees表中，输出first_name按照升序排序后，排名为奇数的first_name。 CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`) ); 输入: emp_no birth_date first_name last_name gender hire_date 10001 1953-09-02 Georgi Facello M 1986-06-26 10002 1964-06-02 Bezalel Simmel F 1985-11-21 10005 1955-01-21 Kyoichi Maliniak M 1989-09-12 10006 1953-04-20 Anneke Preusig F 1989-06-02 输出: Georgi Anneke 如对以上示例数据的first_name排序后的序列为：Anneke、Bezalel、Georgi、Kyoichi。 则原序列中的Georgi排名为3，Anneke排名为1，所以按原序列顺序输出Georgi、Anneke。
示例1

输入

drop table if exists  `employees` ; 
CREATE TABLE `employees` (
  `emp_no` int(11) NOT NULL,
  `birth_date` date NOT NULL,
  `first_name` varchar(14) NOT NULL,
  `last_name` varchar(16) NOT NULL,
  `gender` char(1) NOT NULL,
  `hire_date` date NOT NULL,
  PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12');
INSERT INTO employees VALUES(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02');

输出

Georgi
Anneke
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