This time our child has a simple polygon. He has to find the number of ways to split the polygon into non-degenerate triangles, each way must satisfy the following requirements: each vertex of each triangle is one of the polygon vertex; each side of the polygon must be the side of exactly one triangle; the area of intersection of every two triangles equals to zero, and the sum of all areas of triangles equals to the area of the polygon; each triangle must be completely inside the polygon; each side of each triangle must contain exactly two vertices of the polygon. The picture below depicts an example of a correct splitting. Please, help the child. Calculate the described number of ways modulo 1000000007 (109 + 7) for him.
输入描述:
The first line contains one integer n(3 ≤ n ≤ 200) — the number of vertices of the polygon. Then follow n lines, each line containing two integers. The i-th line contains xi, yi(xi, yi ≤ 107) — the i-th vertex of the polygon in clockwise or counterclockwise order.It's guaranteed that the polygon is simple.
输出描述:
Output the number of ways modulo 1000000007(109 + 7).
示例1
输入
4
0 0
0 1
1 1
1 0
4
0 0
1 0
0 1
-1 0
5
0 0
1 0
1 1
0 1
-2 -1
备注:
In the first sample, there are two possible splittings:In the second sample, there are only one possible splitting:
加载中...