Little Petya loves looking for numbers' divisors. One day Petya came across the following problem: You are given n queries in the form " x i y i ". For each query Petya should count how many divisors of number x i divide none of the numbers x i - y i , x i - y i + 1, ..., x i - 1 . Help him.
输入描述:
The first line contains an integer n (1 ≤ n ≤ 105). Each of the following n lines contain two space-separated integers xi and yi (1 ≤ xi ≤ 105, 0 ≤ yi ≤ i - 1, where i is the query's ordinal number; the numeration starts with 1). If yi = 0 for the query, then the answer to the query will be the number of divisors of the number xi. In this case you do not need to take the previous numbers x into consideration.
输出描述:
For each query print the answer on a single line: the number of positive integers k such that
示例1
输入
6
4 0
3 1
5 2
6 2
18 4
10000 3
备注:
Let's write out the divisors that give answers for the first 5 queries:1) 1, 2, 4 2) 33) 54) 2, 65) 9, 18
加载中...