有一个薪水表，salaries简况如下: emp_no salary from_date to_date 10001 72527 2002-06-22 9999-01-01 10002 72527 2001-08-02 9999-01-01 10003 43311 2001-12-01 9999-01-01 请你找出所有员工具体的薪水salary情况，对于相同的薪水只显示一次,并按照逆序显示，以上例子输出如下: salary 72527 43311
示例1
输入
drop table if exists `salaries` ;
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO salaries VALUES(10001,72527,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');
INSERT INTO salaries VALUES(10003,43311,'2001-12-01','9999-01-01');
加载中...