树的子结构
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题目描述
输入两棵二叉树A，B，判断B是不是A的子结构。（ps：我们约定空树不是任意一个树的子结构）
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树的子结构
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/** public class TreeNode { int val = 0; TreeNode left = null; TreeNode right = null; public TreeNode(int val) { this.val = val; } } */ public class Solution { public boolean HasSubtree(TreeNode root1,TreeNode root2) { } }
/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } };*/ class Solution { public: bool HasSubtree(TreeNode* pRoot1, TreeNode* pRoot2) { } };
# -*- coding:utf-8 -*- # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def HasSubtree(self, pRoot1, pRoot2): # write code here
/* public class TreeNode { public int val; public TreeNode left; public TreeNode right; public TreeNode (int x) { val = x; } }*/ class Solution { public bool HasSubtree(TreeNode pRoot1, TreeNode pRoot2) { // write code here } }
/* function TreeNode(x) { this.val = x; this.left = null; this.right = null; } */ function HasSubtree(pRoot1, pRoot2) { // write code here } module.exports = { HasSubtree : HasSubtree };
<?php /*class TreeNode{ var $val; var $left = NULL; var $right = NULL; function __construct($val){ $this->val = $val; } }*/ function HasSubtree($pRoot1, $pRoot2) { // write code here }
/* function TreeNode(x) { this.val = x; this.left = null; this.right = null; } */ function HasSubtree(pRoot1, pRoot2) { // write code here }