编程题

先用数组存上顺序。然后计数排序就行了

# 我比较菜，抛砖引玉 def sort_str(s): sort_dict = {'A':1.5,'a':1,'B':3.5,'b':3,'C':5.5,'c':5,'D':7.5,'d':7,'E':9.5,'e':9,'F':11.5,'f':11, 'G':13.5,'g':13,'H':15.5,'h':15,'I':17.5,'i':17,'J':19.5,'j':19,'K':21.5,'k':21, 'L':23.5,'l':23, 'M':25.5,'m':25,'N':26.5,'n':26,'O':24.5,'o':24,'P':22.5,'p':22, 'Q':20.5,'q':20,'R':18.5,'r':18,'S':16.5,'s':16,'T':14.5,'t':14,'U':12.5,'u':12, 'V':10.5,'v':10,'W':8.5,'w':8,'X':6.5,'x':6,'Y':4.5,'y':4,'Z':2.5,'z':2} new_dict=dict() not_char=[] error=[] for i in range(len(s)): if s[i].isalpha(): new_dict[s[i]] = sort_dict.get(s[i]) elif s[i].isdigit(): not_char.append(s[i]) else: print('only accept alpha and digit, input contains:') return s[i] ss = list(dict(sorted(new_dict.items(), key=lambda x:x[1])).keys()) return ''.join(ss)+''.join(not_char)