leetcode 题
```
/**
* Definition for singly-linked list.
* type ListNode struct {
* Val int
* Next *ListNode
* }
*/
func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode {
head := &ListNode{Val: 0}
n1, n2, carry, current := 0, 0, 0, head
for l1 != nil || l2 != nil || carry != 0 {
if l1 == nil {
n1 = 0
} else {
n1 = l1.Val
l1 = l1.Next
}
if l2 == nil {
n2 = 0
} else {
n2 = l2.Val
l2 = l2.Next
}
current.Next = &ListNode{Val: (n1 + n2 + carry) % 10}
current = current.Next
carry = (n1 + n2 + carry) / 10
}
return head.Next
}
```
```
/**
* Definition for singly-linked list.
* type ListNode struct {
* Val int
* Next *ListNode
* }
*/
func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode {
head := &ListNode{Val: 0}
n1, n2, carry, current := 0, 0, 0, head
for l1 != nil || l2 != nil || carry != 0 {
if l1 == nil {
n1 = 0
} else {
n1 = l1.Val
l1 = l1.Next
}
if l2 == nil {
n2 = 0
} else {
n2 = l2.Val
l2 = l2.Next
}
current.Next = &ListNode{Val: (n1 + n2 + carry) % 10}
current = current.Next
carry = (n1 + n2 + carry) / 10
}
return head.Next
}
```
2022-05-13
在牛客打卡3天,今天也很努力鸭!
全部评论
相关推荐
点赞 评论 收藏
分享
点赞 评论 收藏
分享
02-11 13:25
燕京理工学院 数据分析师
在笔试的大西瓜很矫健:校招数分不用想了,这经历和学历都不够用,大厂更别想,初筛都过不了,说点不好听的小厂数分都进不去(小厂也是假数分),要两个对口实习+3个项目(或者3+2),而且要有含金量才能补一点你的学历劣势。
建议刷实习,社招找数分,校招看运气,能入行业就行,可以运营转数分 点赞 评论 收藏
分享