题解 | 链表内指定区间反转
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @param m int整型
* @param n int整型
* @return ListNode类
*/
#include <stdlib.h>
struct ListNode* reverseBetween(struct ListNode* head, int m, int n ) {
// write code here
int s = n-m;
int count;
struct ListNode label;
label.next = head;
struct ListNode* pre = &label;
for(count=1;count<m;count++){ //找头节点
pre = pre->next;
}
struct ListNode* now = pre->next;
struct ListNode* new = NULL;
int i = 0;
while(i<n-m){
new = now->next;
now->next = new->next;
new->next = pre->next;
pre->next = new;
i++;
}
return label.next;
}
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