题解 | 统计每个产品的销售情况
统计每个产品的销售情况
https://www.nowcoder.com/practice/d431aa7bf72c4fd7b048ec639bc83ad2
#前5个字段
with t1 as(
select p.product_id,
sum(quantity)*unit_price as total_sales,
unit_price,
sum(quantity) as total_quantity,
round(sum(quantity)*unit_price/12,2) as avg_monthly_sales
from products p
join orders o on p.product_id=o.product_id
group by p.product_id
),
#月最高销量
t2 as(
select product_id,
max(m_quantity) as max_monthly_quantity
from(
select product_id,
sum(quantity) as m_quantity
from orders
group by product_id,month(order_date)
)a
group by product_id
),
#计算每个客户购买量,并排名
t3 as(
select product_id,
b.customer_id,
customer_age,
row_number()over(partition by product_id order by c_quantity desc,customer_age) as rn
from(
select product_id,
customer_id,
sum(quantity) as c_quantity
from orders
group by product_id,customer_id
)b
join customers c on b.customer_id=c.customer_id
)
select t1.product_id,
t1.total_sales,
t1.unit_price,
t1.total_quantity,
t1.avg_monthly_sales,
t2.max_monthly_quantity,
case when t3.customer_age between 1 and 10 then '1-10'
when t3.customer_age between 11 and 20 then '11-20'
when t3.customer_age between 21 and 30 then '21-30'
when t3.customer_age between 31 and 40 then '31-40'
when t3.customer_age between 41 and 50 then '41-50'
when t3.customer_age between 51 and 60 then '51-60'
else '61+' end as customer_age_group
from t1
join t2 on t1.product_id=t2.product_id
join t3 on t1.product_id=t3.product_id
where t3.rn=1
order by t1.total_sales desc,t1.product_id
