题解 | 字符串操作
字符串操作
https://www.nowcoder.com/practice/06a5336b64e3481fbbcc1f7d5cba548d
n, m = map(int, input().split())
s = input()
# 直接按照题目要求写代码
for i in range(m):
shuru = input().split()
l, r, c1, c2 = shuru[0], shuru[1], shuru[2], shuru[3]
l, r = int(l) - 1, int(r) - 1
s = s[0:l] + s[l : r + 1].replace(c1, c2) + s[r + 1 :]
print(s)
海康威视公司福利 1382人发布
查看11道真题和解析
