题解 | 异常的邮件概率
异常的邮件概率
https://www.nowcoder.com/practice/d6dd656483b545159d3aa89b4c26004e
select date, round(sum(if(type='no_completed' ,1,0))/count(*),3) as p
from email
where
send_id in (select id from user where is_blacklist = 0)
and
receive_id in (select id from user where is_blacklist = 0)
group by date
order by date
