题解 | 字母异位词的长度

from collections import Counter


class Solution:
    def isCongruent(self, s: str, c: str) -> int:
        if len(s) != len(c):
            return -1

        count = [0] * 26

        for i in s:
            count[ord(i) - ord("a")] += 1
        for i in c:
            count[ord(i) - ord("a")] -= 1

        for i in range(26):
            if count[i] != 0:
                return -1
        return len(s)