题解 | 吐泡泡

吐泡泡

https://www.nowcoder.com/practice/f86fa2221c094b3d8d1fc79bae450d96

n = int(input())
for i in range(n):
    stack = []
    pp = input()
    for p in pp :
        if stack == []:
            stack.append(p)
        elif p == 'o' and stack[-1] == 'o':
            stack.pop()
            if stack ==[]:
                stack.append('O')
            elif stack[-1] == 'O':
                stack.pop()
            else:
                stack.append('O')
        elif p =='o':
            stack.append(p)
        elif p == 'O' and stack[-1] == 'O':
            stack.pop()
        else:
            stack.append('O')
    print(''.join(stack))

全部评论

相关推荐

评论
点赞
收藏
分享

创作者周榜

更多
牛客网
牛客网在线编程
牛客网题解
牛客企业服务