题解 | 删除字符串中出现次数最少的字符
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
s = input().strip()
# 构造一个字典
freq = {}
# 遍历字符串，若字典中不存在该字符则新增该字符并设置为1，否则在原来基础上自增1
for char in s:
freq[char] = freq.get(char, 0) + 1
# 找到字典中的最小值，待会要用
min_freq = min(freq.values())
# 把所有字典中最小值对应的字符删除
result = [char for char in s if freq[char] != min_freq]
# 字典转换成字符串输出
print(''.join(result))
