题解 | 矩阵转置
矩阵转置
https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841
n,m = map(int,input().strip().split())
matrix = [list(map(int,input().strip().split())) for _ in range(n)]
tran_matrix = [[0]*n for _ in range(m)]
for i in range(n):
for j in range(m):
tran_matrix[j][i] = matrix[i][j]
for row in tran_matrix:
print(" ".join(map(str,row)))
，建议把公司名字爆出来